Using scala-yaml is very easy, all you have to do is import org.virtuslab.yaml.* and write derives YamlCodec after your case class definition. Then you're able to use following extension methods:
as[T]yieldsEither[YamlError, T]trying to convert String instance to the provided typeTasYamlconverts your datatype into yaml-formatted String
import org.virtuslab.yaml.*
case class Address(city: String, zipcode: String) derives YamlCodec
case class Person(name: String, age: Int, address: Address) derives YamlCodec
val yaml = s"""name: John Wick
|age: 40
|address:
| city: Anywhere
| zipcode: 12-345
|""".stripMargin
val decoded = yaml.as[Person]
// Either[YamlError, Person] = Right(Person(John Wick,40,Address(Anywhere,12-345)))
case class Activity(kind: String, distance: Seq[Double]) derives YamlCodec
val activity = Activity("running", Seq(5.37, 4.98, 5.73))
val encoded = activity.asYaml
//kind: running
//distance:
// - 5.37
// - 4.98
// - 5.73
It is important not to omit derives YamlCodec in case class definition otherwise compiler will not be able to create codecs and will fail as shown below:
import org.virtuslab.yaml.*
case class Address(city: String, zipcode: String)
val address = Address("EŁk", "19-300")
address.asYaml